Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 11 2015 at 09:57am)

7a)titan/360×2pie r cos t
d=55/360×2×22/7×640 cos 4
d=55×44×6400 cos 4/2520
d=55×44×6400×0496/2520
d=15,449.28/2520
d=6130.67 d~6130km. ii)distance along gent circle
D=tita/360×2pie r
D=55/360×2/7×22/7×6400/1
D=55×44×6400/2520
D=15,488×6400/2520
D=6144.03 D=~6146km. 7b)
Length of sector tita/360×2pie r
L=120/360×2/1×22/7×42/1
L=120×44×42/2520
L=221760/2520 L=88cm
L=2pie r Where r is the radius of
circumference
88=2×22/7×r
88×7=44r R=88×7/44
R=616/44
R=14cm. Curved surface area
= pie rc
A=22/7×14×42/1 A=22×14×4^2/7
A=12936/7
A=1848cm^2.
8a) X=60/t ———->(i)
Y=180/t ———->(ii) T1=60/X
T2=100/Y
T1+T2=5
60/X+180/Y = 300 ———->(i)
180/X + 60/Y = 260 ———->(ii) Let P =1/X 2 = 1/Y
60p + 180 Q = 300
180p + 6Q = 200
P + 3Q =5
9P + 3Q =13
Substract (i)from (ii) 8p = 8 P = 8/8 ÷ P = 1
Subtract P into (i)
P + 3Q =5
1 + 3Q =5
3Q =5-1 3Q =4
Q = 4/3 P = 1 ÷ 1 = 1/X ÷ X = 1
4/3 = 1/Y ÷ Y = 3/4
8b)
2001 ——— 25,700 2002 ———
15/100 X 25,700 +
25,700 = 29,555 Amount of tax in 2002
= 29,555 * 12.5/100
= N3694.375
=N3690 8c)
Log25
Log16 25/100 Log16 2/4
Log4 6-1
-1/2 Log4^4 -1/2
===========================
9ai)
W=K+C/2 24 = k+ C/16
384 = 16K + C ——-(i) 18 = K + C/4
72 + 4K + C ———(ii)
16K + C = 384
4K + C = 72
Substact (ii) from (i) 12k/12 = 312/12 K = 26
Substract K into (i)
16k + C = 384
C = 384 – 416
C = -32
W=k+C/t2 W=26-32/t2 (ii)
When W= -46,t=?
-46 = 26 -32/t2
t2 = -32/-72
t = Sqrt 16/36 = 4/6 =2/3
9b) V = Pie r2 . d = 14,r = 7cm
1232 = 22/7 * 7^2 * h
h = 7*1232/22*49
h = 8624/1074 h = 8cm
===========================
11a) y^1=x^2(3x+1)^2
v=(2x+1)^2
v=m^2 dm/dx=2
dv/dm=2m
dy/dx=dv/dm×dm/dx
=2m×2 =4m
dy/dx=4(2x+1) dy/dx=udv/dx+v whole
no. dy/dx
=x^2 4(xx+1)^2,×3x
=4x^2(2x+1)+2x(2x+1)^2.
11b) [3 3-1]
[1 0 2] [3 – 2 3]
+2[0-(-4)-3[63]
+-1(-2)
8+9+2
=19. 11c) m=y2-y1/x2-x1
y-y1= m(x-x2)
m=4-3/-1-2
m=-1/3
y1-y2=-1/3(x-x2)
y-3=1/3(x-2) y-3=-4/3+2/3 3y=-x+11
y=-1/3x+11/3

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 11 2015 at 09:58am)

NECO
Maths Type D 1 -10 : ABADCEBAED
11 -20 : BBBAEBABEE
21 - 30: AEBCDAEDDB
31 - 40: DCDEBCBCDB
41 - 50: BEBDBEDEDA 51 - 60: CABBEEBABC MTH OBJ Type A
1 -10 : DEDEDADBDA
11 -20 : BBDADCDACC
21 - 30: BBCCAEBABA
31 - 40: AADEDDBABC
41 - 50: CCADEDECCA 51 - 60: DBEBDABAAD

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 15 2015 at 12:31pm)

PHYSIC OBJ TYPE C:
1-10:DDCADDBCDC
11-20:ECACECCCBC
21-30:EEABBBEDEE
31-40:BECEBADDEC
41-50 :BDDBAEDEDB 51-60:DAEACDBEDC PHYSICS OBJ TYPE C
1D -I and II only
2D-3.34*10^-7N
3C-4.0*10^3
4A-332ms^-1
5D-0.45m 6D-saxophone and trumpet
7B-sqrootVR^2+(Vc-VL)^2
8C-copper
9D-II and III only
10C-4.84&10^-19J
11E-3.3*10^-10Ns 12C-Focusing collector
13A-benue
14C-recieves signal
15E-transportation
16C-101K
17C-prevent electric sparks 18C-R and RM
19B-5.0s
20C-173.2J
21E-80.0%
22E-Venier calipers and spring balance
23A-centrifugal 24B-360m
25B-beyond 2f
26B-52.50cm
27E-shekere
28D-diffusion
29E-I,II and III 30E-Neutrons
31B-5ohm
32E-400.0Vm^-1
33C-I and III only
34C13.30cm
35B-Hot body and thermophile 36A-before,before
37D-26.7mm
38D-10.5
39E-80.00mmHg
40C-7.74N
41B-(x-z)/(x-y) 42D-240m
43D-interchanging the polarity of the
magnet
44B-minimize energy losses
45A-perforator
46E-15/16 47D-Y and X-Y
48E-(E2-E1)h^-1
49D-magnet is moving away from the
coil
50B-150V
51D-VL leads IL by pie/2 rad 52A-A red surface appearing black
when
viewed under green light
53E-Sun and firefly
54A-2.0
55C-methane 56D-inertia
57B-Burning of firewood
58E
59D-momentum and weight
60C-w^2/2x

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 15 2015 at 12:37pm)

Theory Part 1a
i.Insulated wire
iimagnet
iiicopper coil. 1B.
i. A rocket can work anywhere even in
space.
ii. A rocket is fast and thus saves time.
iii. Rockets are used for space shuttles. 1C
i They are applicable in the heating of
swimming pool water.
ii. They can be applied as solar panels. 3a.
A trajectory is the curved path of an
object that has been fired or thrown/ a
path followed by a projectile. 3B.
i.The force
ii. The mass of the body.
iii. The surface area of the projectile No9
In silver plating a spoon,it is made from
the cathode of an electrolytic cell. The
anode is a bar of silver metal,
and the electrolyte (the liquid in
between the electrodes) is a solution of silver cyanide, AgCN, in water. When
a direct current is passed
through the cell, positive silver ions (Ag
+) from the silver cyanide
migrate to the negative anode (the
spoon), where they are neutralized by electrons and stick to
the spoon as silver metal:
Meanwhile, the silver anode bar gives
up electrons to become silver
ions:
Thus, the anode bar gradually dissolves to replenish the silver ions in
the solution. The net result is that silver
metal has been transferred
from the anode to the cathode, in this
case the spoon. This process
continues until the desired coating thickness is built up on the spoon-
usually only a few thousandths of an
inch-or until the silver bar has
completely dissolved. (2)
Given; d=10units
R(6,4) and S(2,K)
d=sqroot(y2-y1)^2+(x2-x1)^2
10^2=(k-4)^2+(2-6)^2
100=k^2-8k+16+16 k^2-8k+32-100=0
k^2-8k-68=0
k=8+_sqroot(8^2-4*1*-68)/2
k=8+_sqroot(64+272)/2
k=8+_sqroot(64+272)/2
k=8+_sqroot(336)/2 k=8+_18.3/2
k=8-18.3/2 or 8+18.3/2
k=-5.15 or 13.15 (4)
Velocity ratio(V.R)=1/sintita
4=1/sintita
sintita=1/4
tita=sin^-1(0.25) (7)
This is because the speed of sound
decreases
as temperature increases.On hot day
the
temperature in high hence the speed decreases while on cold day,the speed
increases because temperature is
lowered (8)
Given;length(l)=2.0m
Resistance(R)=3.0ohm
Diameter(d)=0.8mm
d=0.8*10^-3m
Resistivity=? R=el/A
A=(pie*d^2)/4
=3.142/4*(0.8*10^-3)^2
A=(3.142*0.64*10^-6)/4
A=0.50*10^-7m^2
A=5*10^-7m^2 3.0=(e*2)/(5*10^-7)
e=(15*10^-7)/2
Resistivity(e)=7.5*10^-7nm (5a)
Energy is the ability to do work while
power is
the rate expended (5b)
Given mass of man(m)=72kg
height(h)=5m
time(t)=40s
p=mgh/t=energy/time
p=(72*10*5)/40 p=90W (12a)
-Sugar tongs->third class
-Nutcracker->second class
-Bottle opener->first class (12b)
(i)Archemedes' principle states that a
body
which is wholly or partially immersed
in a fluid
,experiences loss in wheight which is equals
to weight of fluid displaced
(ii)This is due to the resulting apparent
weight
of the object in liquid which is less than
true weight 12c)
Given; mass(m)=500g=0.5kg Force
constant(k)=4Nm^-1
i)Period (T)=w=sqroot(k/m)
=sqroot(4/0.5)
w=sqroot(8) =2.83rad/s
w=2*pie*f w=2*pie(1/T)
2.83=(2*3.142)/T
T=(2*3.142)/2.83
=2.22s
ii)frequencyf=1/T f=1/2.22 =0.45Hz 14a)
landa=wavelength
x=wave distance
v=velocity/speed 14b)
i)The eye is a natural optical device
while
camera is artificial optical device
ii)-Both eye and camera are used as
optical device -Both eye and camera use lenses 14c)
i)Resonance is a phenomenon where
by
a
vibrating body sets another body
vibrating both having the same natural frequency
ii)Length(L)=45cm=0.45m
L=landa/2 0.45=landa/2
landa=0.45*2=0.90m
v=f*landa
340=fo*0.90 fo=340//0.90
fo=377.8Hz
===================
15a)
i)-its presence gives charge
-its presence bring spark -its presence bring light
ii)The presence of charge is responsible
for moving charges 15b)
i)-it is used for radio turning
-it is used to reduce spark
ii)-Area of over-lap between the plates
-Dustance of seperation between the
plates 15c)
Force(Fxy)=1.13*10^11N
(Fzx)=3.60*10^11N
i)Resultant force(Fzy)=R
R=sqroot(Fxy^2+Fzx^2)
R=sqroot (1.13*10^11)^2+(3.60*10^11)^2
R=sqroot(1.28*10^22+12.96*10^22)
R=sqroot(14.24*10^22)
R=3.78*10^11N
ii)tan tita=(3.60*10^11)/(1.13*10^11)
=3.19 tita=tan^-1(3.19)=72

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 15 2015 at 12:37pm)

Theory Part 1a
i.Insulated wire
iimagnet
iiicopper coil. 1B.
i. A rocket can work anywhere even in
space.
ii. A rocket is fast and thus saves time.
iii. Rockets are used for space shuttles. 1C
i They are applicable in the heating of
swimming pool water.
ii. They can be applied as solar panels. 3a.
A trajectory is the curved path of an
object that has been fired or thrown/ a
path followed by a projectile. 3B.
i.The force
ii. The mass of the body.
iii. The surface area of the projectile No9
In silver plating a spoon,it is made from
the cathode of an electrolytic cell. The
anode is a bar of silver metal,
and the electrolyte (the liquid in
between the electrodes) is a solution of silver cyanide, AgCN, in water. When
a direct current is passed
through the cell, positive silver ions (Ag
+) from the silver cyanide
migrate to the negative anode (the
spoon), where they are neutralized by electrons and stick to
the spoon as silver metal:
Meanwhile, the silver anode bar gives
up electrons to become silver
ions:
Thus, the anode bar gradually dissolves to replenish the silver ions in
the solution. The net result is that silver
metal has been transferred
from the anode to the cathode, in this
case the spoon. This process
continues until the desired coating thickness is built up on the spoon-
usually only a few thousandths of an
inch-or until the silver bar has
completely dissolved. (2)
Given; d=10units
R(6,4) and S(2,K)
d=sqroot(y2-y1)^2+(x2-x1)^2
10^2=(k-4)^2+(2-6)^2
100=k^2-8k+16+16 k^2-8k+32-100=0
k^2-8k-68=0
k=8+_sqroot(8^2-4*1*-68)/2
k=8+_sqroot(64+272)/2
k=8+_sqroot(64+272)/2
k=8+_sqroot(336)/2 k=8+_18.3/2
k=8-18.3/2 or 8+18.3/2
k=-5.15 or 13.15 (4)
Velocity ratio(V.R)=1/sintita
4=1/sintita
sintita=1/4
tita=sin^-1(0.25) (7)
This is because the speed of sound
decreases
as temperature increases.On hot day
the
temperature in high hence the speed decreases while on cold day,the speed
increases because temperature is
lowered (8)
Given;length(l)=2.0m
Resistance(R)=3.0ohm
Diameter(d)=0.8mm
d=0.8*10^-3m
Resistivity=? R=el/A
A=(pie*d^2)/4
=3.142/4*(0.8*10^-3)^2
A=(3.142*0.64*10^-6)/4
A=0.50*10^-7m^2
A=5*10^-7m^2 3.0=(e*2)/(5*10^-7)
e=(15*10^-7)/2
Resistivity(e)=7.5*10^-7nm (5a)
Energy is the ability to do work while
power is
the rate expended (5b)
Given mass of man(m)=72kg
height(h)=5m
time(t)=40s
p=mgh/t=energy/time
p=(72*10*5)/40 p=90W (12a)
-Sugar tongs->third class
-Nutcracker->second class
-Bottle opener->first class (12b)
(i)Archemedes' principle states that a
body
which is wholly or partially immersed
in a fluid
,experiences loss in wheight which is equals
to weight of fluid displaced
(ii)This is due to the resulting apparent
weight
of the object in liquid which is less than
true weight 12c)
Given; mass(m)=500g=0.5kg Force
constant(k)=4Nm^-1
i)Period (T)=w=sqroot(k/m)
=sqroot(4/0.5)
w=sqroot(8) =2.83rad/s
w=2*pie*f w=2*pie(1/T)
2.83=(2*3.142)/T
T=(2*3.142)/2.83
=2.22s
ii)frequencyf=1/T f=1/2.22 =0.45Hz 14a)
landa=wavelength
x=wave distance
v=velocity/speed 14b)
i)The eye is a natural optical device
while
camera is artificial optical device
ii)-Both eye and camera are used as
optical device -Both eye and camera use lenses 14c)
i)Resonance is a phenomenon where
by
a
vibrating body sets another body
vibrating both having the same natural frequency
ii)Length(L)=45cm=0.45m
L=landa/2 0.45=landa/2
landa=0.45*2=0.90m
v=f*landa
340=fo*0.90 fo=340//0.90
fo=377.8Hz
===================
15a)
i)-its presence gives charge
-its presence bring spark -its presence bring light
ii)The presence of charge is responsible
for moving charges 15b)
i)-it is used for radio turning
-it is used to reduce spark
ii)-Area of over-lap between the plates
-Dustance of seperation between the
plates 15c)
Force(Fxy)=1.13*10^11N
(Fzx)=3.60*10^11N
i)Resultant force(Fzy)=R
R=sqroot(Fxy^2+Fzx^2)
R=sqroot (1.13*10^11)^2+(3.60*10^11)^2
R=sqroot(1.28*10^22+12.96*10^22)
R=sqroot(14.24*10^22)
R=3.78*10^11N
ii)tan tita=(3.60*10^11)/(1.13*10^11)
=3.19 tita=tan^-1(3.19)=72

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 22 2015 at 08:32am)

ECONOMICS TYPE D 1-10 CCEBBCCADD 11-20 DCEECADABA
21-30 ECCDADABAE Question 6 == List five factors banks consider before granting loans to customers 7a)Explain internal and External trade. 7b)Lst five problems of international trade.

Member

merrylarry

Re- 2015 neco June/July ssce time table

(Jun 22 2015 at 09:48am)

ECONOMICS OBJ
Econs-Type A
1-10DADDDCBBEA
11-20 DEBCCACABE
21-30 CEAAAAABDE
31-40 DCECDBBAEC 41-50 AAABDDCCCC
51-60 EDECCDBDBE TYPE D
1-10 CCEBBCCADD
11-20 DCEECADABA
21-30 ECCDADABAE
31-40 BDACC-EECDC
41-50 BBBEDC-D-A 51-60 DCCBAEEDCA. ECONOMICS ANSWER
Q1.
Year |Population | Working Pop 2000 |
45 |20 2001. |60 |35 2002. |70 |48
2003 |80 |60 2004. |105 |75
1a) Population increase of growth rate in 2001 is
= New - Old population
= 60,000 - 45,000
= 15,000 Population growth rate in 2001 is =
15,000/45,000 x 100 = 33.33%
Growth pop. in 2003 is
= 80,000 - 70,000
= 10,000 Growth rate is = 10,000/70,000 x 100
= 14.29% Growth pop in 2004 is = 105,000 -
80,000
= 25,000 Growth rate is = 25,000/105,000 x 100
= 23.81% 1b) Percentage of working from 2002 -
2004
In 2002
Working pop = 45
Total pop = 70
= 45/70 x 100 = 64.28% In 2003
Working pop = 60
Total pop = 80
= 60/80 x 100 = 75% In 2004
Working pop = 78
Total pop= 105
= 78/105 x 100
= 74.21%
Total % from 2002 to 2004 is 78 + 60 + 45 / 255 x 100
= 77.77% 1c.
factors that can stimulate increase in
population of a country. i. early marriage: peaple that who
engage in early marriage and this leads
to having many chirldren thereby
increasing the size of country
population. ii. inprove medical services: the
availability of medical sevices has
helped to reduce tha rate of death,
hence population is sure to increase
under this condition. iii. increase in birth rate: when thre is
increase in bith rate as its desired in
every family to have many chirldren in
west African countries, so as the
population os such countries inreased No6) Just choose five -The type of Account The Customer
operates: Although non-account
owners get loans, loans are normally
given to current account owners more
than those who operate savings
accounts. - The Amount Involved: If it is a large
sum of loan, the Bank Manager will
consider whether if such an amount is
removed, it will not affect the financial
standing of the bank. -The Past Financial Dealings of the
Customer with the Bank: one with
sound past financial dealings with a
bank has a higher chance of getting a
loan and vice versa.(from 9jahub.com) -The Earning Power of The Customer:
The person's earnings vis-a-vis the
amount to be given out as loan are
some of the determining factors in
granting and issuing loans. -The Collateral Security Offered:These
collateral securities which are fixed
assets must be the things the bank can
sell easily and more than the value of
the loan given. -The Period of Repayment: The period
of re-payment of such loan is very
important because, the Bank would not
want its loan to be tied down for a
very long time in spite of the fact that
it changes interest on the loan. (8)
- The income of the customer
- Close substitute of a commodity
- Nature of commodity
- Ones habit
- Number of users to which a commodity is put
THE INCOME OF THE CUSTOMER: The
higher the consumers income, the more
inelastic his demand for goods and
services will tend to be. CLOSE SUBSTITUTE OF A COMMODITY:
Commodities which have close
subtitles tend to have a high price
elasticity of demand while those that
do not have close substitutes are likely
to be elastic. NATURE OF COMMODITY: Whether the
commodity is a necessity or a luxury
items will affects the elasticity of
demand. ONES HABIT: when one forms a habit
on the consumption of a commodity, a
change in the price of that commodity
will not affects ones demand for it. NUMBER OF USERS TO WHICH A
COMMODITY IS PUT: It is known that the
more a commodity can be put into
several uses, the more elastic the
demand becomes and vice versa.(from
9jahub.com) (9a) MONOPOLISTIC COMPETITION: Is a
market situation which combines the
fundamental characteristics of both
pure monopoly and perfect
competition. This type of market
situation exists because neither pure monopoly nor perfect competition
exists in isolation and this is a result of
absence of homogeneity and
heterogeneity of products sold in both
markets.(from 9jahub.co