Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 10:38am

4a) Sum of 3(2/3) and 2(1/5) =3(2/3) +
2(1/5) =11/3 + 11/5 =(55+33)/15
=88/15 =5.87 Amount=7-5.87 =1.13
=7-5(13/15) =7-(88/15) =17/15

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 10:39am

(4b)
i)h=6+4cos(15p)degrees h=6+4cos
(15*4) h=6+4cos60degrees h=6+(4*0.5)
h=6+2 =8m ii)9=6+4cos(15p)degrees
4cos(15p)degrees=3 Cos15p=3/4 =0.75
15p=Cos^-1(0.75) 15p=41.4 P=41.4/15 =2.76

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 11:31am

5a) Area of trapezium =1/2(a+b)*h =1/2(20+60) * 40 =40*40 =1600cm^2 5b) <QRS=90degrees(right angle)

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 12:53pm

ObJ Answers
1-10 BAABDCDBCB
11-20 ADDBCCCDCC
21-30 BDCBDBBACA
31-40 CADCDCDDDA
41-50 CDDDBABACD

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 12:54pm

check if it tally with ur qst

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 12:57pm

dont use it yet its wrng

Member

merrylarry

Re: waec may/June assistance

Apr 23 2015 at 01:32pm

VERIFIED MATHS OBJ
1CCBCCCABCD
11CBBACABBCB
21BBCCDABDCA
31ACBADBDADA
41CAABBABBAB