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(Sep 20 2014 at 09:50am)

Math answer

Q1b

5x-4y=6...,....1

3^3(y-x) = 1/27....2

From......2

3^3y-3x= 1/3^3

3^3y-3x = 3-3

3y-3x=-3

Y=-1+x.........2

Substitute 2 in 1

5x-4 (-1+x)=6

5x-4(-1+x)=6

X+4=6

X=6-4

X=2

From.....2.

y=-1+2=1

Y=1

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(Sep 20 2014 at 10:01am)

(1)

Given, m^2 - 2mn + n^2 - 9r^2

m^2 - 9r^2 + n^2- 2mn

m^2 - (3r)^2 + n(n-2m)

(m-n)^2 - 9r^2

=(m - n - 9r)(m -n +9r)

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(Sep 20 2014 at 10:12am)

(3a)
QT(power)2 =QS(power)2 + ST(power)2
5(power)2 =4(power)2 + ST(power)2
ST(power)2 =25 - 16
ST(power)2 =9
ST=sqrt (9)= 3cm
Cos(tita)=3/5
cos(tita)= 0.6
tita= cos(power)-1(0.6) = 53degree
cos53(degree)=SR/6
0.602 =SR/6
SR= 0.602*6 = 3.6cm
/TR/=3.6/Sin53(degree)=4.5cm
(3b)
Adj=12
Opp=5
Hyp=13
cosx=12/13
Sinx=5/13,
Tanx=5/12
Cosx - 2Sinx/2Tanx = 12/13-2(5/13) /
2(5/12)
= (12/13 - 10/13) / 5/6
= (2/13) / (5/6)
= 2/13*6/5
= 12/65

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(Sep 20 2014 at 10:19am)

Q4b
X=(10'11'12'13'14'15)
Y= (10'12'14'16)
Xy=(10'11'12'13'14'15'16'17'18'19'20)
Xny= (10"12"14)
(2A)
All taxable income is
= 10% + 15% + 20% + 25%
= 70% of 850
= 70/100*850
= #595
(2B)
1: 70/100*120 =#84
2: 70/100*30= #21
3: 70/100*100 =#70
4: 70/100*40 = #28
total= 84+21+70+28=#203
=203 +595
=#798.
Xny=(10)

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(Sep 20 2014 at 10:22am)

(4a)
Log10(75/10) - Log10(5/9)(power)2 +
Log10(100/243)
= Log10(75/10) - Log10(25/81) +
Log10(100/243)
= Log10(75/10*81/25) +
Log10(100/243)
= Log10(3*81/10) + Log10(100/243)
= Log10(243/10) + Log10(100/243)
= Log10( 243/10* 100/243)
=Log10(10)=1

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(Sep 20 2014 at 10:22am)

(4a)
Log10(75/10) - Log10(5/9)(power)2 +
Log10(100/243)
= Log10(75/10) - Log10(25/81) +
Log10(100/243)
= Log10(75/10*81/25) +
Log10(100/243)
= Log10(3*81/10) + Log10(100/243)
= Log10(243/10) + Log10(100/243)
= Log10( 243/10* 100/243)
=Log10(10)=1

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(Sep 20 2014 at 10:33am)

(5a)
Considering change in WZX
ZX(power)2 = Zw(power)2 + WX
(power)2
ZX(power)2 = 6(power)2 + 8(power)2
= 36+ 64
ZX(power)2=100
ZX= sqrt(100)
=10cm
ZX= 2ZM
ZM= ZX/2
Zm=10/2 =5cm
Mx=5cm
OM is the height of the pyramid
OX(power)2= OM(power)2 + MX
(power)2
13(power)2= OM(power)2 + 5(power)2
169= OM(power)2 + 25
OM(power)2 = 169 -25
OM(power)2 = 144
OM= sqrt(144)
=12cm
height of pyramid = 12cm
(5b)
COS < 0XZ = 12/13
<OXZ= cos(power)-1(0.9231)
<OXZ=22.6(degree)